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We have [7]_{5} = [2]_{5} and [9]_{5} = [4]_{5}. Consequently,

[7+9]_{5}= [2+4]_{5}= [6]_{5}= [1]_{5}.

When dealing with e.g.

[3]_{5}= {..., -7, -2, 3, 8, 13, ...}

we need not take the "canonical" representative 3 but may also choose -2 or 8 as the representative for computation.

Author: Wolfgang Schreiner

Last Modification: January 12, 2000