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Time op0 op1 op2 op3 0 a0 1 a1 a0 2 a2 a1 a0 3 a3 a2 a1 a0 4 a4 a3 a2 a1 ... ... ... ... ... n an an-1 an-2 an-3
4n/(4+n) clock cycles required to process n elements!